On the expansions of analytic functions on convex locally closed sets in exponential series

Автор: Melikhov Sergej Nikolaevich, Momm Siegfried

Журнал: Владикавказский математический журнал @vmj-ru

Статья в выпуске: 1 т.13, 2011 года.

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Let Q be a bounded, convex, locally closed subset of CN with nonempty interior. For N>1 sufficient conditions are obtained that an operator of the representation of analytic functions on Q by exponential series has a continuous linear right inverse. For N=1 the criterions for the existence of a continuous linear right inverse for the representation operator are proved

Короткий адрес: https://sciup.org/14318338

IDR: 14318338

Текст научной статьи On the expansions of analytic functions on convex locally closed sets in exponential series

In the late sixties Leont’ev (see [10]) proved that each analytic function f on a convex bounded domain Q C can be expanded in an exponential series j N c j exp(λ j · ). This series converges absolutely to f in the Fr´echet space A(Q) of all functions analytic on Q, and its exponents λ j are zeroes of an entire function on C which does not depend on f A(Q). A formula for the coefficients of a some expansion in such exponential series (with the help of a system orthogonal to (exp(λ j · )) j N ) was obtained only for the analytic functions on the closure of Q. Later similar results for the analytic functions on convex bounded domain Q C N were obtained by Leont’ev [9], Korobeinik, Le Khai Khoi [3] (if Q is a polydomain) and Sekerin [15] (if Q is a domain of which the support function is a logarithmic potential).

In [4, 5, 11] was investigated a problem of the determination of the coefficients of the expansions of all f A(Q), where Q is a convex bounded domain in C, in following setting. Let K C be a convex set and suppose that L is an entire function on C with zero set (λ j ) j N and with the indicator H Q + H K , where H Q and H K is the support function of Q resp. of K. By Λ 1 (Q) we denote a Fr´echet space of all number sequence (c j ) j N such that the series j N c j exp(λ j · ) converges absolutely in A(Q). In [4, 5, 11] were established the necessary and sufficient conditions under which a sequence of the coefficients (c j ) j N Λ 1 (Q) in a representation f = j N c j exp(λ j · ) can be selected in such way that they depend continuously and linearly on f A(Q). In other words, in [4, 5, 11] was solved the problem of the existence of continuous linear right inverse for the representation operator R : Λ 1 (Q) A(Q), c 7→ j N c j exp(λ j · ). Note that in [4, 5] a formula for continuous linear right inverse for R (if it exists) was not obtained.

In the present article we consider the following situation. Let Q C N be a bounded convex set with nonempty interior. We assume that Q is locally closed, i. e. Q has a fundamental sequence of compact convex subsets Q n , n N. By A(Q) we denote the space of all analytic functions on Q with the topologie of proj n A(Q n ), where A(Q n ) is endowed with natural (LF)-topologie. We put e \ (z) := exp(P N=1 A m z m ), λ, z C N . For an infinite set M C N N , for a sequence (A (k) ) (k) G M C C N N with | A (k) | ^ ^ as | (k) | ^ ^ we define a locally convex space Л 1 (Q) of all number sequence (c (k) ) (k) G M such that the series ^(k^M C ( k ) e \ (k) converges absolutely in A(Q). The representation operator c ^ ^2(k)eM c ( k ) e ^ (k) maps continuously and linearly Л 1 (Q) into A(Q). We solve the problem of the existence of a continuous linear right inverse for R.

In this paper for N >  1 we assume that (A (k) ) ( k )^ M is a subset of zero set of an entire function L on C N with “planar zeroes” and with indicator H Q + H K , where H Q and H K are the support functions of Q resp. of some convex compact set K C N . By [15] such function L exists if and only if the support function of clQ + K is so-called logarithmic potential (for N = 1 a function L exists for each Q and each K). In contrast to [4, 5] here we do not use the structure theory of locally convex spaces. As in [11], we reduce the problem of existence a continuous linear right inverse for the representation operator to one of an extension of input function L to an entire function L on C 2N satisfying some upper bounds. With the help of L we construct a continuous linear left inverse for the transposed map to R . Using -technique, we obtain that the existence of such extension L is equivalent to two conditions, namely, to the existence of two families of plurisubharmonic functions, first of which is associated only with Q and second is associated with K and Q . The evaluation of first condition was realized in [21]. For the evaluation of second condition we adapt as in [21] the theory of the boundary behavior of the pluricomplex Green functions of a convex domain and of a convex compact set in C N which was developed in [23, 25].

For N = 1 we obtain more complete results. In the first place we prove the criterions for the existence of a continuous linear right inverse for R without additional suppositions on Q and K . Secondly, with the help of a function L as above we give a formula for a continuous linear right inverse for R .

  • 1.    Preliminaries

    • 1.1.    Notations. If B C N , by cl B and int B we will denote the closure and the interior of B , respectively. By int r B , r B we denote the relative interior and the relative boundary of B with respect to a certain larger set. For notations from convex analysis, we refer to Schneider [26].

    • 1.2.    Definitions and Remarks. A convex set Q C N admitting a countable fundamental system ( Q n ) n N of compact subsets of Q is called locally closed. Let Q C N be a locally closed convex set. We will write ω := Q r Q , where r Q denotes the relative boundary of Q in its affine hull. By [21, Lemma 1.2] ω is open in r Q . We may assume that the sets Q n are convex and that Q n C Q n+i for all n E N. A convex set Q C C N will be called strictly convex at r ω if the intersection of Q with each supporting hyperplane to cl Q C N is compact. If int Q 6 = ∅, Q is strictly convex at r ω if and only if each line segment of ω is relatively compact in ω .

By [13, Lemma 3] Q C N is strictly convex at r ω if and only if Q has a fundamental system of convex neigborhoods.

  • 1.3.    Convention. For the sequel, we fix a bounded, convex and locally closed set Q C N with 0 in its nonempty interior and with a fundamental system of compact convex

subsets Q n C Q n+i , n E N. By (^ n ) n G N we shall denote some fundamental system of compact subsets of ω = Q r Q.

K will always denote a compact convex set in C N .

  • 1.4.    Notations. For each convex set D C N we denote by H D the support function of D, i. e. Hd (z) := sup w G D Re h z, w i , z E C N . Here h z, w i := P N=1 z j W j . We put H n := H Q n , n N.

Let e λ (z) := exp h λ, z i , λ, z C N . For a locally convex space E by E b 0 we denote the strong dual space of E.

  • 1.5.    Function spaces. We set | z | := h z, z) 1/2 , z E C N ; U (t, R) := { z E C N : | t - z | < R } , t E C N , R> 0; U := U (0,1). For all n,m E N let E nm := A ^ (Q n + ml U ) denote the Banach space of all bounded holomorphic functions on Q n + 1 U , equipped with the sup-norm. We consider the spaces A ( Q n ) = m N E n,m of all functions holomorphic in some neighborhood of Q n , n N, and endow them with there natural inductive limit topology. By A ( Q ) we denote the vector space of all functions which are holomorphic on some neighborhood of Q . We have A ( Q ) = n N A ( Q n ), and we endow this vector space with the topology of A ( Q ) := proj n A ( Q n ). This topology does not depend on the choice of the fundamental system of compact sets ( Q n ) n N . If Q is open, A ( Q ) is a Fr´echet space of all holomorphic functions on Q .

For all n, m N let

An,m := If E A(CN): kf kn,m := sup |f (z)| exp ( - Hn(z) - |z|/m) < ro) z∈CN and

A Q := ind proj A n,m . n m

  • 1.6.    Duality. The ( LF )-space A ( Q ) := ind n A ( Q n ) 0 b and A Q are isomorphic by the Laplace transformation

F : A ( Q ) 0 A Q , F( ϕ )( z ):= ϕ ( e z ) , z C N .

In addition ( LF )-topology of A ( Q ) 0 equals the strong topology.

The assertion has been proved in [21, Lemma 1.10] (see Remark after 1.10, too)

If we identify the dual space of A ( Q ) with A Q by means of the bilinear form , ·i , then h e λ , f i = f ( λ ) for all λ C N and all f A Q .

  • 1.7.    Sequence spaces. Representation operator. Let M N N be an infinite set and (A (k) ) (k) G M C C N be a sequence with | A (k) | ^ ro as | (k) | ^ ro . For all n,m E N we introduce the Banach spaces

Л n,m (Q) := ^c = (c (k) ) ( k )G M C C : ^2 | c (k) | exp (H n (A (k) ) + | A (k) | /m) <  ГО p

(k) G M

Kn,m(Q) := ^c = (c(k))(k)GM C C : sup |c(k)| exp ( - Hn(A(k)) -|A(k)|/m) < ro^ (k)GM and put

Л 1 (Q n ) := indЛ nJm (Q), Л 1 (Q) := projЛ 1 (Q n ), K ^ (Q) :=indproj K n,m (Q). m →                 n                n m

We note that the series ^( k ^^ M c ( k ) e\w converges absolutely in A(Q) if and only if c E Л 1 (Q) (see [2,Ch.I, §§ 1,9]).

The operator R(c) := ^Z( k) G M c ( k ) e \ (k) maps continuously and linearly Л 1 (Q) in A(Q). We call R the representation operator. By Korobeinik [2], if R : Л 1 (Q) ^ A(Q) is surjectiv, (e ^ ( k ) ) (k) G M is called an absolutely representing system in A(Q).

Let e ( k ) := ( k ) , ( m ) ) (m) G M , (k) E M , where S^m ) is the Kronecker delta.

  • 1.8.    Duality. ( i ) The transformation ^ ^ (^(e ( k ) )) (k) G M is an isomorphism of (LF )- space Л 1 (Q) ' := ind n , Л 1 (Q n ) b onto K ^ (QY The duality between Л 1 (Q) and K ^ (Q~) is defined by the bilinear form h c,d) := ^2(k) G M c ( k ) d ( k ) .

  • (ii)    A transposed map R' : Aq ^ K ^ (Q) to R : Л 1 (Q) ^ A(Q) is the restriction operator f ^ (f(\ k) )) (k) G M

  • ( iii )    R has a continuous linear right inverse if and only if R 0 has a continuous linear left inverse.

C The assertions (i) and (ii) were in [13, Lemma 6] proved.

(iii): This can be proved in the same way as ( i ) ( ii ) in [21, Lemma 1.12]. (We note that we can not assume in advance the surjectivity of R .) B

  • 1.9.    Notations. Let S := { z C N : | z | = 1 } . For a convex set D C N , γ D and A S we define

Sγ(D) := {a ∈ S : Rehw, ai = HD(a) for some w ∈ γ} and

F A ( D ) := { w D : Re h w, a i = H D ( a ) for some a A } .

We will write S Y := S Y (Q), A := S f a ( k ) (K), S o := S \ S ^

Definition 1.10. (a) Given an open subset B S and a compact convex set K C N . K is called smooth in the directions of the boundary of B if for each compact set κ B the compact set К := Sf k (k ) (K ) is still contained in B .

Note that the condition is fulfilled if dK is of class C 1 .

  • (b) A convex compact set K C N is called not degenerate in the directions of B S , if K is not contained all in the supporting hyperplane { z C N Re h z, a i = H K ( a ) } of K for each a B .

Note that the condition is fulfilled if int K 6 = ∅.

Remark 1.11. (a) Under the hypotheses of the Definition 1.10 (a) the following holds: Let S 1 C S be an open neighborhood of S \ B (with respect to S). For к := S \ S 1 , the set к is a compact subset of B. Hence if S 2 C S \ K is compact, we have S 2 П к = 0 and thus S 2 C S 1 . (Otherwise it would follow that К П S 2 = 0.)

  • (b) Let K have 0 as an interior point. K is smooth in the directions of the boundary of B if and only if the convex set intK 0 U w ' is strictly convex at d r w ' , where w ' := dK 0 П Г(В), K 0 := { z E C N | Hk (z) 6 1 } and Г(В) := { tb 1 1 > 0 } .

  • 2. Conditions of existence of a continuous linear right inverse for the representation operator

  • 2.1.    Notations, Definitions and Remarks. (a) Let f be an entire functions of exponential type on C N . By h f we denote the (radial) indicator of f , i. e.

h f ( z ) := lim sup(lim sup log | f ( rz 0 ) | /r ) for all z C N .

z'^z   r ^ + ro

  • (b)    An entire function f of exponential type on C is called function of completelly regular growth (by Levin–Pflu¨ger), if there is a set of circles U(µ j , r j ), j N, with | µ j | → ∞ as j ^ го , such that lim R .^ R P^ j | r j = 0 and outside of U^ n U (^ j ,r j ) the following asymptotic equality holds:

log I f (z) l = h f (z) + o( | z | ) as | z | ^ го .

By Krasichkov–Ternovskii [6], in Definition (b) we can choose the exclusive circles U (µ j , r j ) so that they are mutually disjoint.

  • (c)    By Gruman [18] an entire function f of exponential type on C N is called function of completelly regular growth, if for almost all a S the function f (az) of one complex variable has completelly regular growth on C.

  • (d)    There are other definitions of the functions of completelly regular growth of Azarin [1] and of Lelon, Gruman [8, Ch. IV, 4.1]. By Papush [14], if f is an entire function on C N with “planar” zeroes, i. e. the zero set { z C N : f(z) = 0 } of f is the union of the hyperplanes { z C N : h z, a k i = c k } , a k S, c k C, k N, all these definitions (for f ) are equivalent. From this and from [7, 22] it follows that an entire function f on C N with “planar” zeroes has completely regular growth on C N if and only if f is slowly decreasing on C N .

  • 2.2.    A special entire function. A structure of the exponents A (k) . (a) Below we shall exploit an entire function L on C N of order 1, which satisfies the following conditions: (i) The zero set V (L) of L is a sequence of pairwise distinct hyperplanes P k := { z C N : h a k z i) = C k } , k 6 N, where | a k | = 1 and C k = 0. If for k 1 < k 2 < ... <  k N the intersection P k 1 П P k 2 П ... П P k N is not empty, then it consits of a single point A (k) , where (k) denotes multiindex (k i ,k 2 ,..., k N ). Further M is the set of the such multiindexes (k). Moreover, L (k) (A (k) ) = 0, where Lw(z) := L(z)/lw(z) and lw(z) := lj =i« a k j , z ) — C k 3 ), (k) 6 M . (ii) L is a function of completely regular growth with indicator H Q + H K .

We recall the some definitions and results from Sekerin [15].

  • (iii)    | L (k) (A (k) ) | =exp(H Q (A (k) ) + Hk (Aw )+ o( | A fe) | >) as | (k)M го .

We write l k (z) := h a k , z i - c k , z C N , k N.

  • (b)    (i) By [15, Theorem 1], for each f 6 A int q+k the Lagrange interpolation formula holds:

    f (A) = X '    f ^ A 6 C N



where the series converges uniformly on compact sets of C N . From (1) it follows that (A (k) ) (k) G M is the uniqueness set for A int q+k , i. e. from f 6 A(C N ), h f (z) <  H q (z) + Hk (z) for all z C N \{ 0 } it follows that f 0.

  • (ii)    There is a function a(z) = o( | z | ) as | z | ^ го such that | L (k) (z) | 6 exp(H Q (z) + H K (z) + α(z)) for all z C N and all (k) M.

  • (c)    A plurisubharmonic function u on C N will be called a logarithmic potential if there exists a Borel measure ^ > 0 on [0, го ) x S N such that for every R 6 (0, го ) there is a pluriharmonic function u R on U(0, R) with

    u(z) =


    log | t - h z, w i| dµ(t) + u R (z)


    for all z U (0, R).


[0,R] x S N

By [15] for a bounded convex domain D with 0 ∈ D the support function HD is a logarithmic potential for example if D is a polydomain, a ball, an ellipsoid, a polyhedra with symmetric faces, and in the case of C2 , if D = D1 + iD2 , where D1 and D2 are any centrally symmetric convex domains in R2; if D is symmetric with respect to 0 and cl D is a Steiner compact set (see Matheron [19, § 4.5]).

For each bounded convex domain D C with 0 int D the function H D is a logarithmic potential.

  • (d)    By [15, Theorem 5], there exists a function L satisfying the conditions (i)–(iii) in 2.2 (a) if and only if H Q + H K is a logarithmic potential. H Q + H K is a logarithmic potential if H Q and H K are the logarithmic potentials.

  • (e)    Let H Q+K = H Q +H K be a logarithmic potential. By [15] the representation operator R : Λ 1 (intQ + K) A(int Q + K) is surjective. By [13, Theorem 14] R : Λ 1 (Q) A(Q) is surjective, if Q is strictly convex at ∂ r ω, K is smooth in the directions of ∂ r S ω and not degenerate in the directions of S ω .

Theorem 2.3. Let Q be strictly convex at ∂ r ω and L be an entire function on C N satisfying the conditions 2.2 (a). Then (II) (III) (I):

  • (I)    The representation operator R : Λ 1 (A) A(Q) has a continuous linear right inverse.

  • (II)    There is a positively homogeneous of order 1 plurisubharmonic function P on C 2N such that P(z,z) >  Hq(z) + H K (z) and ( V n) ( 3 n') ( V s) ( 3 s ' ) with

P(z, ц) 6 H n (z) + | z | /s + Hk (ц) + Hq(^) H n (^) - l^ /s' ( V z, ц G C N ).

  • (III)    There are the plurisubharmonic functions u t ,v t , t G S , on C N such that u t (t) >  0, v t (t) > 0 and ( V n) ( 3 n ' ) ( V s) ( 3 s ' ) with

  • (a)    u t (z) 6 H n o (z) H n (t) + | z | /s 1/s ' and

  • (b)    v t (ц) 6 Hk (ц) + Hq(^) H n (^) Hk (t) - H Q (t) + Н п (t) Ws + 1/s for all z,^ G C N and all t S .

  • <1 (II) ^ (III). We may choose

u t ( z ) := P ( z, t ) - H Q ( t ) - H K ( t ) ,   v t ( µ ) := P ( t, µ ) - H Q ( t ) - H K ( t )

for all z, µ C N and t S .

  • (III) (II). We put

Po(z,^):= (sup (ut(z) + vt(ц) + Hq(z) + Hk(ц))^ , z,^ G CN, where f∗ denotes the regularization of a function f . P0 is the plurisubharmonic function on C2N with

P(z,z) >  Hq(z) + Hk (z) ( V z G S).

By (III) we have: (∀ m) (∃ n0) (∀ s) (∃ r) with ut(z) 6 Hn0(z) — Hm(t) + |z|/s — 1/r for all z G CN and all t G S and (∀n) (∃ m) (∀r) (∃ s0) with vt(ц) + Hq(€) + Hk(t) 6 Hk(ц) + Hq(p-) — Hn(^) + Hm(t) — |ц|/s + 1/r for all µ ∈ CN and all t ∈ S. By adding the last inequalities, we obtain that (∀n) (∃ n0) (∀ s) (∃ s0) with ut(z) + ^(ц) + HQ(t) + HK(t) 6 Hn0(z) + HK(ц) + HQ(^) — Hn(^) + |z|/s — |ц|/s'

for all z,p E C N and t E S . From this it follows that P g satisfies the upper bounds in (II). As P we may choose P (z,p) := (limsup t ^ + ^ P (tz,tp)/t) * , z,p E C N .

  • (III)    ⇒ (I). By (the proof of) [16, Theorem 4.4.3] (see [8, Theorem 7.1], too) there is a L E A(C 2N ) with L(z, z) = L(z) and ( V n) ( 3 n 0 ) ( V s) ( 3 s 0 ) ( 3 C ): ( V z,p E C N )

    We define


    l L(z,p) l 6 C exp (H ^ (z) + | z | /s + Hk (p) + H q (p) - H n (p) - | p | /s 0 ).


    ˜


    ˜

    / X/ X              L (k) (z)L(z, A (k) )

    К 1 <С)(2):= £.   L(k) ^    '


    c K (Q), z C N .



From (2) it follows that the series in (3) converges absolutely in A 2q+k . (By [21, Remark 1.5] 2Q + K is locally closed and (2Q n + K) n N is a fundamental system of compact subsets of 2Q + K .) Hence k 1 maps K ^ (Q) in A 2 q + k continuously (and linearly). Since, by (2), for all f E Aq and z E C N the function L(z, f belongs to A int q + k , by 2.2 (b) for all z E C N

˜

K i (R 0 (f ))(z) = £ L ( k ) ( z ) L(z,X ( k ) ) f ( X ( k ) ) = L(z,z)f (z) = L(z)f (z). (k) G M        л (k))

From here it follows that K i R 0 is the operator of multiplication by L. By [21, Proposition 2.7] there is a continuous linear left inverse K 2 : A 2 Q + K ^ Aq for K i R 0 . The operator к := K i ok2 is a continuous linear left inverse for R 0 .

Now we shall evaluate the abstract condition (III) (b) of Theorem 2.3. The condition (III) (a) was evalueted in [21, Proposition 3.6]. B

We recall some definitions from [23] and [25].

Definition 2.4. If D C C N is bounded, convex and c >  0, let v H D c be the largest plurisubharmonic function on C N bounded by H D and with v H D c (z) 6 c log | z | + O(1) as | z | ^ 0. A function C H D : S ^ [0, 00] is defined by

{z E C N : v H D ,c (z) = H D (z)} = {Aa : a E S, 1/C H D (a) 6 A <  0 }.

If 0 int D and if C > 0, let v H D ,C be the largest plurisubharmonic function on C N bounded by H D and with v H D ,C (z) 6 C log | z | +O(1) as | z | → ∞ . A function C H 0 : S [0, ] is defined by

{z E C N : v ^ D ,c (z) = H D (z)} = {Aa : a E S, 0 6 A 6 1/C H D (a)} .

Instead C H D and CHI D we shall write briefly C D resp. C ^ .

Proposition 2.5. Let Q be strictly convex at the ∂ r ω and suppose that 0 int K. For N > 1 assume that K is smooth in the directions of ∂ r S ω . The following are equivalent:

  • (i)    There are plurisubharmonic functions v t (t S) on C N with v t (t) > 0 such that: ( n) ( n 0 ) ( s) ( s 0 ) with

v t 6 H K + H Q - H n - | · | /s 0 - H K (t) - H Q (t) + H n 0 (t) + 1/s ( t S).

  • (ii)    1/C K is bounded on some neighborhood of S g and C I is bounded on each compact subset of S ω .

C (i) ⇒ (ii). Choose n0 according to (i) for n = 1. On So we have Hn0 < HQ. Thus there are a neigborhood S of So and some ε > 0 with Hn0 + ε 6 HQ on S . We put v := sup(vt + HK (t)) ∗. tes

This function is plurisubharmonic on CN with v > HK on S and satisfies: (∀ n) (∃ n0) (∀ s) (∃ s0 ) such that v 6 HK + | · |/n + max{-HQ(t) + Hn0} + 1/s.

t S

Since H n 0 6 H Q , this gives v 6 H K on C N . The bounds for n = 1 give v(0) 6 - ε.

From [25, 2.14] it follows that 1/C K is bounded on S.

Let κ ⊂ Sω . We define v := st∈uκp(vt + HK (t)) ∗ .

This function is plurisubharmonic on C N with v > H K on κ and satisfies: ( n) ( n 0 ) ( s) ( s 0 ) such that v 6 H K + H Q - H n - | · | /s 0 + 1/s 6 H K + H Q - H n + 1/s. This shows that v 6 H K .

Now choose n with κ S ω n , i. e. with H Q = H n on κˆ. Choose n 0 > n according to (i). Choose s 0 for s = 1. Then there is a neighborhood κ˜ of κ in S such that

HQ - Hn - | · |/s0 6 -| · |/(2s0) on Γ(κ˜) and thus v 6 HK - | · |/(2s0) + 1 on Γ(κ˜).

In order to reach our claim that C K is bounded on κ, we need an estimate like the previous one on all C N (not only on the particular cone). For this purpose we are going to modify v . First note that, if N = 1, it follows from what we have already proved that ∂K has to be of class C 1 (see [20, 2.10, 2.14]). For N >  1 we use our special hypothesis. For this reason we may assume that we have constructed v for the set κ ˆ instead of κ .

Define

L ( z ) := sup Re h w, z i ,   z C N .

w F κ

The positively homogeneous function L satisfies L 6 H K on C N , and L = H K on κ . If L ( a ) = H K ( a ), there is w F κ with Re h w, a i = H K ( a ), hence a S F κ . Thus L < H on S outside the compact set κ ˆ. We replace v by v ˜ := v/ 2 + L/ 2 and obtain v ˜ 6 H K on C N , v ˜ = H K on κ and v ˜ < H K outside a neighborhood of the origin. By [23, 2.1] this shows that C K is bounded on κ .

  • (ii)    ^ (i). By the hypothesis, 1/C K is bounded on some neighborhood S of S q . Hence there is c > 0 such that the plurisubharmonic function v H K c equals H K on S . Let n N. Since H n ^Iq on S q , there is a co^mpact neighborhood Sn of S q ^^ith ^in ^^Q on S n . ^We may assume S n C S n -i C ... C S i C S . Since C K is bounded on S \ S n , there is C n > 0 with v n := v U k ,C n = Hk on S \ S n+2 .

Again for N = 1 it follows from (ii) that dK is of class C i . For N >  1 we apply the extra hypothesis to obtain (as in the first part of the proof) a positively homogeneous function L n bounded by H on C N , which equals H on к = S n+i , and such that L n H outside the compact set S n+i C S n (see Remark 1.11 (a)). Then the plurisubharmonic function v n := v H K ,c /2 + L n /2 satisfy v n 6 Hk on C N , v n = Hk on S n+i , V n 6 (H k + L n )/2 <  Hk on S \ S n .

Fix n E N. Since vn 6 (Hk + Ln)/2 < Hk + Hq — Hn on S, and since vn(0) < 0, there is n˜ with vn 6 Hk + Hq — Hn - D/2 - 1/n on CN, were D:=HK+HQ-Hn-(HK+Ln)/2=(HK-Ln)/2+HQ-Hn.

Choose n0 with Hq — Hn0 6 1/n on Sn+1. Then for each s there is s0 with D/2 > | • |/s0 on CN such that vn 6 HK + HQ — Hn — I • |/s0 — HQ(t) + Hn0(t) + 1/s (Vt E Sn+1)-

For the functions v n we get: Choose n 0 (in addition) so large that H Q = H n 0 on S \ S n +2 . For each s we choose s 0 (in addition) so large that vn3 6 Hk - ЫА0 + 1/s (see Definition 2.4). This gives

< 6 H K + H Q H n — 1| /s 0 H Q (t) + H n 0 (t) + 1/s ( V t E S \ S n+2 )-

Note that v0 > ... > vn > vn+1 and that v0 6 - - - 6 v0 6 vnO+r That is why for each l ∈ N the following holds: (∀n) (∃ n0) (∀ s) (∃ s0) with v0 6 HK + HQ — Hn — 1 • |/s0 — HQ(t) + Hn0(t) + 1/s (vt E Sn+1), and (∀n) (∃ n0) (∀ s) (∃ s0) with v0 6 HK + HQ — Hn — 1 • |/s0 — HQ(t) + Hn0 (t) + 1/s (V t E S\Sn+2)

By the construction, lim l →∞ v l 0 =: v 0 exists and defines a plurisubharmonic function with v 0 = H K on S 0 .

For t S \ S 2 define v˜ t := v 1 . For t S l+1 \ S l+2 we put v˜ t := v l 0 /2 + v l /2. For t S 0 we define v˜ t := v 0 . Obviously v˜ t (t) = H K (t) for all t S.

Let t E Si+1\Si+2. For n 6 l and n0, s and s0 as above we get vt 6 (Hk + Hq — Hn — | • |/s0 — HQ(t) + Hn0(t) + 1/s)/2 + Hk/2-

By the strict convexity of Q at ∂rω (see [21], the proof of Proposition 3.6), there is n00 such that (HQ + Hno )/2 6 Hnoo and thus (HQ — Hno )/2 > HQ — Hn. This gives vt 6 HK + HQ — Hn — 1 • |/(2s0) — HQ(t) + Hn00(t) + 1/(2s)-

For n > l and n0, s and s0 as above we get vt 6 Hk/2 + (Hk + Hq — Hn — | • |/s0 — HQ(t) + Hn0(t) + 1/s)/2-

As above we get the desired estimate.

For t S 0 =    l N S l , we see as in the first part of the previous arguing that v˜ t = v 0

satisfies these estimates for all n (6 l = ro ).

For t S \ S 2 , as in the second part of the arguing just done, we see that these estimates hold for all n (> l = 1).

Finally we put v t := v t Hk (t), t E S and are done. B

Remark 2.6. Let Q be strictly convex at the ∂ r ω. By [21, Proposition 3.6] the following are equivalent:

  • (i)    There are plurisubharmonic functions u t (t S) on C N with u t (t) > 0 such that: ( n) ( n 0 ) ( s) ( s 0 ) with

u t (z) 6 H n 0 (z) - H n (t) + | z | /s - 1/s 0 ( z C N , t S).

  • (ii)    C q is bounded on some neighborhood of S 0 and 1/Cq is bounded on each compact subset of S ω .

  • 3. The case of one complex variable

Theorem 2.7. Let Q be strictly convex at the ∂ r ω and suppose that 0 int K and L is a function as in 2.2 (a). For N > 1 assume that K is smooth in the directions of ∂S ω . If C Q and 1/C K are bounded on some neighborhood of S 0 , 1/C q and Ck are bounded on each compact subset of S ^ then the representation operator R : Л 1 (Q) ^ A(Q) has a continuous linear right inverse.

C The assertion hold by Theorem 2.3, Proposition 2.5 and Remark 2.6. B

The equivalent conditions of Theorem 2.7 are fulfilled if ∂Q and ∂K are of H¨older class C 1,л for some A > 0. They are not fulfilled if Q or K is a polyedra, and for N = 1 if dQ or ∂K has a corner [24].

In this section we consider the case N = 1 for which the results of the previous sections can be improved.

Convention 3.1. Further L is an entire function on C satisfying following conditions:

  • (i)    The zero set of L is a sequence of pairwise distinct simple zeros λ k , k N, such that | A k | 6 | A k+i | for each k E N.

  • (ii)    L is a function of completely regular growth with indicator H Q + H K .

  • (iii)    The asymptotic equality holds:

| L 0 ( λ k ) | = exp( H Q ( λ k ) + H K ( λ k ) + o ¯( | λ k | )) as k → ∞ .

Such function L exists (see for example [10]).

Leont’ev (see [10]) introduced an interpolating function, which is defined with the help of an entire function of one complex variable. Leont’ev’s interpolating function is a functional from A (cl Q + K ) 0 \ A ( Q ) 0 for every K (if Q 6 = cl Q ). With the help of an entire function of two complex variables we give the analogous definition of an interpolating functional from A ( Q ) 0 .

Definition 3.2. Let L be an entire function on C 2 such that L( ^ , ц) E Aq for each µ C. Q -interpolating functional we shall call a functional

t

Q l (z,^,f) := F - 1

Ес,ц))^ If (t £)exp(z£) d^y 0

z,µ C , f A ( Q ) ,

where the integral is taken along the interval [0 , t ].

We show certain properties of Ql .

Lemma 3.3. (a) Ql ( ,ц,f ) E Aq for all ц E C and f E A(Q).

  • (b)    For all z, ц E C the equality Ql (z, z, e ^ ) = 1(ц, z) holds where a function l E A(C 2 ) is such that L ( µ, z ) - L ( z, z ) = l ( µ, z )( µ - z ) .

  • (c)    Q ^ (ц, z, ) E A(Q) for all z, ц E C.

C (a): We fix µ C, f A(Q) and a domain G with Q G and f A(G). We choose a contour C in G which contains in its interior the conjugate diagram of L( · , µ). If γ( · , µ) is Borel conjugate of L( · , µ), we have:

t

Q l (z,^,f) = 2П J y (t,^ I J

f(t - ξ)exp(zξ)dξ dt, z C.

C        \0                   /

Since the function (t, ^) ^ y (t, ^) (J ot f (t - ^)exp(z^) d^ is continuous by t E C and entire by z, the function Q l (z,^,f) is entire (with respect to z). From direct upper bounds for | Q l (z,^,f) | it follows that Q l (^,f) E A q .

(b): Obvious.

(c): Since the map f ^ Jt f (t £)exp(z£) d^ , t E Q, is continuous and linear in A(Q) and F - 1 (Q( - ,^)) is a continuous and linear on A(Q), the functional Qq(z,^, ) is continuous and linear on A(Q), too. B

Lemma 3.4. We assume that a function L, as in 3.2, satisfies in addition the following conditions: L˜ (z, z) = L(z) for each z ∈ C and (∀n) (∃ n0) (∀s) (∃ s0) (∃ C) with lL(z,^)l 6 Cexp (Hn(z) + Hk(д) + HqM — HnM + |z|/s — |^|/s°) (Vz, д E C).

Then n(f) := (Ql (X k , X k , f )/L 0 (X k )) k ^ N , f E A(Q), is continuous linear operator from A(Q) into Л 1 (Q).

C We define L k (z) := L(z, λ k )/(L 0 k )(z - λ k )), k N. By using upper bounds for | L | , 3.1 (iii) and 3.3 (b), we obtain, that L k is entire function on C and ( n) ( n 0 ) ( s) ( s 0 ) ( 3 C 1 , C 2 ) such that for all z E U(X k , (1 + | X k | ) - 2 )

lL k (z) | 6 C 1 exp (H n 0 (z) + H K ( X k ) + H Q ( X k ) H n ( X k ) + | z | /s — | X k | /(s' 1) +2log(1 + | X k | ) log | L 0 (X k ) | ) 6 C 2 exp (H n 0 (z) H n ( X k ) + | z | /s — | X k | /s 0 )   ( V k E N )-

Applying the maximum principle we get that ( V n) ( 3 n 0 ) ( V s) ( 3 s 0 ) ( 3 C 3 ) with

\ L k (z) | 6 C 3 exp (H n o (z) H n (X k ) + | z | /s — | X k | /s 0 ) ( V z E C, k E N).

From this it follows that the series P k ^ N C k L k converges absolutely in A q for each c = (c k ) k e N E K ^ (Q) and к : c ^ P k ^ N C k L k is continuous linear operator from K ^ (Q) into A q . We shall find its adjoint operator к 0 : A(Q) ^ Л 1 (Q):

h c,K (e ^j i = h K(c),f i = <^X c k L k ,e^

k N

= 52 C k L k (^) = 52 C k Q L (X k , X k , e M )/L 0 (X k ) ( V ^ E C, c E Л 1 (Q)). k N           k N

Hence к 0 ^ ) = (Ql (X k , X k , e ^ )/L 0 (X k )) k ^ N , ^ E C. Let C N be a space of all number sequence with its natural topologie. The maps κ 0 : A(Q) C N and Π : A(Q) C N are continuous and linear. Since the set { e µ : µ C } is total in A(Q), we have Π = κ 0 on A(Q) and Π is continuous and linear from A(Q) into Л 1 (Q). B

Theorem 3.5. (I) Let 0 int r K. The following assertions are equivalent:

  • (i)    The representation operator R : Л 1 (Q) ^ A(Q) has a continuous linear right inverse.

  • (ii)    There is an entire function L on C 2 such that L(z,z) = L(z) and ( V n) ( 3 n ' ) ( V s) ( s 0 ) ( C ) with

| L(z,^) | 6 Cexp (Hn- (z) + Hk M + Hq(^) - H n (^) + | z | /s - Ws )  ( V z, д G C).

  • (iii)    Q is strictly convex at d r w, the interior of K is not empty, C q and 1/C K are bounded on some neighborhood of Sq , 1/C Q and C ^ are bounded on each compact subset of S ^ .

  • (II)    (iv) If L is a function as in ( ii ) , the operator

n(f) ^ (Ql(Xk, Xk, f )/L'(Xk))k^N, f G A(Q), is a continuous linear right inverse for R.

(v) If П : A(Q) ^ Л 1 (Q) is a continuous linear right inverse for R, then there is a unique function IL as in (ii) such that H(f) = (Ql (X k ,X k ,f )/L ' (X k )) k G N , f G A(Q).

C (iv) (and (ii) (i)): Let L be a function as in (ii). Then

κ : c

c k

(k) e N

L ˜ ( · , λ k )

L 0 ( λ k )( · - λ k )

maps continuously (and linearly) K ( Q ) into A Q . Since for each f A Q the function fL ( z, · ) belongs to A intQ+K , taking into account the Lagrange interpolation formula (1), we obtain:

˜ ад x f ■•■ L4 LLLLk V,=x f (Xk)L(z.Xk) ,/ k∈N      L (λk)(z - λk) k∈N              L(λk)(z-λk)

= L ( z, z ) f ( z ) = L ( z ) f ( z ) ( z C , f A Q ) .

This implies that κ = Π 0 is a left inverse for R 0 . By the proof of Lemma 3.4 κ is the adjoint to Π for each function L as in (ii). Hence Π is a right inverse for R .

( i ) ( ii ): Let Π be a continuous linear right inverse for R . Then κ := Π 0 : K ( A ) A Q is a left inverse for R 0 . We put f k := K(e ( k ) ), where e ( k ) := (^ k,n ) n G N , k G N. By Grothendieck’s factorization theorem, for each n there is n 0 such that κ maps continuously proj ←m K n,m ( Q ) in proj ←m A n 0 ,m . Hence the following holds: ( n ) ( n 0 ) ( s ) ( r ) ( C ) with

| f k (z) | 6 C exp (H o (z) - H n (X ( k ) ) + | z | /s - | X (k) | /r) ( V z G C, k G N).

For f A Q let

T z (f)(^) := X ^(4“(z X k )f k (z)f (X k ), ^ G C.

k N µ - λ k

By 2.2 (b) (ii) and (4) the series converges absolutely in A Q and converges uniformly (by µ ) on compact sets of C. Fix z C. Then T z ( µf )( µ )) = µT z ( f )( µ ) for all f A Q and µ C. By [12, Lemma 1.7] there is a function a z A (C) such that T z ( f )( µ ) = a z ( µ ) f ( µ ) for all µ C, f A Q . The function L ( z, µ ) := a z ( µ ), z, µ C, satisfies the conditions in (ii) (see the proof of (i) (ii) in [12, Theorem 1.8] too).

  • (iii)    ⇒ (i) holds by Theorem 2.7.

  • (i)    ^ (iii): Since the operator R has a continuous linear righ inverse, R : Л 1 (Q) ^ A(Q) is surjectiv. By [13, Theorem 8] the set Q is strictly convex at ∂ r ω.

Since (i) is equivalent to (ii) there is a function L which satisfies the conditions in (ii). Let P be the (radial) indicator of L, i. e.

Л- ML^z,^) \

P (z, µ) := lim sup                  , z, µ C.

  • t ^+ro        t

Then P is a plurisubharmonic function on C2 satisfying the conditions in (II) of Theorem 2.3. Hence, by Theorem 2.3, there are subharmonic functions vt (t ∈ S) as in (III) (b). We put gt(µ) := |t|vt/|t| (µ/|t|), µ, t ∈ C, t 6= 0. Then gt are subharmonic functions on C such that gt(t) > 0 and (V n) (3 n0) (V s) (3 s0) with gtM 6 HKM + HQM — HnM — HK(t) — HQ(t) + Hn0(t) — M/s0 + |t|/s for all µ, t ∈ C, t 6= 0. If Sω = ∅, the set Q is open. Hence the following holds: (∀ n) (∃ n0) with gt(д) 6 Hk(д) - Hk(t) + |^|/s0 -|t|/s (V^,t G C, t = 0).

Then, by [12, Proposition 1.17], an angle with the corner at 0 doesn’t exist in which the support function HK of K is harmonic. Hence int K = ∅. If Sω = ∅, there is an open (with respect to S) subset A of S such that Hn = HQ on A for large n. Let Γ(A) := {ra : r > 0}. Then for each s there is s0 with gt(д) 6 Hk(д) - Hk(t) + |t|/s - M/s' (V^,t G C, t = 0).

As in [12, Proposition 1.17] from the maximum principle for harmonic functions it follows that the interior of K is not empty.

By Theorem 2.3 , Proposition 2.5 and Remark 2.6 C q and 1/C K are bounded on some neighborhood of S q , 1/C q and C ^ are bounded on each compact subset of S ^ .

(v): By the proof of (i) (ii) there is an entire function L satisfying the conditions in (ii) and such that n 0 (e(fc}) = T,,L(,^k\ x for each k G N. Hence П 0 (с) = Ptpм c^ T,,L(,^k\ x (k )'      L '^k )( Д к )                                              ^k fc N ^L 0 к )( . — Д к )

for each c G K ro (Q) and n(f) = (Q l (A ^ , A ^ , f )/L 0 ( >> k )) k ^ N for all f G A(Q) (see the proof of Lemma 3.4). We shall show uniqueness of such function L. Let L i , L 2 be two such functions. Then L 1 (z,A k ) = L 2 (z,A k ) for all k G N, z G C. Since { A k : k G N } is the uniqueness set for A intQ+K (see 2.2 (b)) and L i (z, ^ ),L 2 (z, ) G A intQ+K , we get L i (z, ) = L 2 (z, ) for each z G C and, consequently, L 1 = L 2 on C 2 .

Acknowledgement. The first named author thanks for the support by the Deutscher Akademis-cher Austauschdienst during his stay at the University of Du¨sseldorf in autumn 2005.

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